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EXERCISE 4.1 · Q11

Q.Prove by method of induction, for all n∈Nn \in N: (24n−1)(2^{4n}-1) is divisible by 1515.

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Let P(n):24n−1=15mP(n):2^{4n}-1=15m; note 24n=16n2^{4n}=16^n. Base: n=1n=1: 16−1=1516-1=15; holds. Hypothesis: assume 16k−1=15a16^k-1=15a, i.e. 16k=15a+116^k=15a+1. Step: 16k+1−1=16(15a+1)−1=240a+16−1=240a+15=15(16a+1)16^{k+1}-1=16(15a+1)-1=240a+16-1=240a+15=15(16a+1), a multiple of 15. **Co …

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