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EXERCISE 4.1 · Q13

Q.Prove by method of induction, for all n∈Nn \in N: 5+52+53+…+5n=54(5n−1)5 + 5^2 + 5^3 + \ldots + 5^n = \dfrac{5}{4}(5^n - 1).

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Let P(n):5+52+⋯+5n=54(5n−1)P(n):5+5^2+\cdots+5^n=\dfrac54(5^n-1). Base: n=1n=1: L.H.S.=5=5, R.H.S.=54(4)=5=\dfrac54(4)=5; holds. Hypothesis: assume true for kk. Step: add 5k+15^{k+1}: $\dfrac54(5^k-1)+5^{k+1}=\dfrac54\cdot5^k-\dfrac54+5\cdot5^k=5^k\left(\dfrac54+5\right)-\dfrac54=5^k\cdot\dfrac{25}{4}-\dfrac54=\dfrac54(5\cdot5^k-1)=\dfrac54(5^ …

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