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EXERCISE 4.1 · Q15

Q.Given that (recurrence relation) tn+1=5tn+4t_{n+1} = 5t_n + 4, t1=4t_1 = 4, prove by induction that (general statement) tn=5n−1t_n = 5^n - 1.

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Let P(n):tn=5n−1P(n):t_n=5^n-1. Base: n=1n=1: 51−1=4=t15^1-1=4=t_1; holds. Hypothesis: assume tk=5k−1t_k=5^k-1. Step: tk+1=5tk+4=5(5k−1)+4=5k+1−5+4=5k+1−1t_{k+1}=5t_k+4=5(5^k-1)+4=5^{k+1}-5+4=5^{k+1}-1, matching P(k+1)P(k+1). Conclusion: by induction, $t_n=5^n-1 …

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