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Exercise 5.1 · Q43

Q.Solve the following inequality and write the solution set using interval notation: x² − x > 20.

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Rewrite as x2−x−20>0x^2-x-20>0. Factoring: (x−5)(x+4)>0(x-5)(x+4) > 0. The critical points are x=5x=5 and x=−4x=-4, dividing the number line into three regions. Testing: for x<−4x<-4 (e.g. x=−5x=-5): (−5−5)(−5+4)=(−10)(−1)=10>0(-5-5)(-5+4) = (-10)(-1) = 10 > 0 ✓. For −4<x<5-4<x<5 (e.g. x=0x=0): (0−5)(0+4)=(−5)(4)=−20<0(0-5)(0+4) = (-5)(4) = -20 < 0 ✗. For x>5x>5 (e.g. x=6x=6): $(6-5)(6+4) = (1)(10) = 10 > …

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