If A = x/6x²+x-15 = 0, B = x/2x²-5x-3 = 0, C = x/2x²-x-3 = 0 then find (A∩B∩C).

Exercise 5.1 · Q9

Q. If A = {x/6x²+x-15 = 0}, B = {x/2x²-5x-3 = 0}, C = {x/2x²-x-3 = 0} then find (A\capB\capC).

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From the previous part, $A=\left\{\frac{3}{2}, -\frac{5}{3}\right\}$ , $B=\left\{-\frac{1}{2}, 3\right\}$ , $C=\left\{\frac{3}{2}, -1\right\}$ . A value must belong to all three sets to be in $A \cap B \cap C$ . $\frac{3}{2}$ is in A and C but not in B. $-\frac{5}{3}$ is only in A. $-\frac{1}{2}$ and $3$ are only in B. $ …

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Q.If A = {x/6x²+x-15 = 0}, B = {x/2x²-5x-3 = 0}, C = {x/2x²-x-3 = 0} then find (A∩B∩C).

Concept understanding — Intersection of Sets

Q.If A = {x/6x²+x-15 = 0}, B = {x/2x²-5x-3 = 0}, C = {x/2x²-x-3 = 0} then find (A∩B∩C).

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