Skip to content
Exercise 5.1 · Q45

Q.Solve the following inequality and write the solution set using interval notation: 6x² + 1 ≤ 5x.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
38% · 45/117 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Rewrite as 6x2−5x+1≤06x^2 - 5x + 1 \le 0. Using the quadratic formula, discriminant =(−5)2−4(6)(1)=25−24=1= (-5)^2-4(6)(1) = 25-24 = 1, so roots are x=5±112x = \frac{5\pm1}{12}, giving x=612=12x=\frac{6}{12}=\frac{1}{2} or x=412=13x=\frac{4}{12}=\frac{1}{3}. Since the coefficient of x2x^2 is positive (the parabola opens upward), the expression 6x2−5x+16x^2-5x+1 is ≤0\le 0 exactly between its two roots …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.