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Exercise 5.1 · Q15

Q.If A = {1, 2, 3, 4}, B = {3, 4, 5, 6}, C = {4, 5, 6, 7, 8} and universal set X = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, then verify: A = (A∩B)∪(A∩B').

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A∩B={1,2,3,4}∩{3,4,5,6}={3,4}A\cap B = \{1,2,3,4\}\cap\{3,4,5,6\} = \{3,4\}. B′=X−B={1,2,7,8,9,10}B' = X-B = \{1,2,7,8,9,10\}, so A∩B′={1,2,3,4}∩{1,2,7,8,9,10}={1,2}A\cap B' = \{1,2,3,4\}\cap\{1,2,7,8,9,10\} = \{1,2\}. Union: (A∩B)∪(A∩B′)={3,4}∪{1,2}={1,2,3,4}=A(A\cap B)\cup(A\cap B') = \{3,4\}\cup\{1,2\} = \{1,2,3,4\} = A. Verified: every element of A either lies in B (captured by A∩BA\cap B) or lies outside B (cap …

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