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Choose the most correct option · Q3

Q.Which one of the following compounds has the highest boiling point ?
a. n-Butylamine b. sec-Butylamine c. isobutylamine d. tert-Butylamine

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Step 1. Recall the intermolecular-force ranking (section 13.4.1). Intermolecular hydrogen bonding is strongest in PRIMARY amines (two N-H hydrogens available), weaker in SECONDARY amines (one N-H), and absent in TERTIARY amines (only weaker dipole-dipole forces from polar C-N bonds).

Step 2. Classify each option. n-Butylamine and isobutylamine are both PRIMARY amines (one group on nitrogen); sec-Butylamine is a... actually sec-butylamine, CH3-CH2-CH(CH3)-NH2, is also a PRIMARY amine by nitrogen-substitution count, just built on a branched/sec-alkyl carbon skeleton; tert-Butylamine, (CH3)3C-NH2, is likewise primary by the nitrogen rule. Re-reading the four options against Table 13.3's own worked comparison (row 1 n-C4H9NH2, a primary amine, 350.8 K, versus row 6 (CH3)3C-NH2, also primary but far more branched, 318.15 K): among primary-amine ISOMERS, boiling point still falls as branching increases, because a more compact, branched molecule has less surface area for the same hydrogen-bonding network to act over.

Step 3. Rank by branching. n-Butylamine (straight chain, least branched, most surface area for hydrogen bonding) has the highest boiling point of the four positional/branching isomers; tert-butylamine (most branched, most compact) has the lowest, matching Table 13.3's own 350.8 K vs 318.15 K comparison.

✓Final answer

a. n-Butylamine

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