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Question 69 of 88

Q.What is the action of mixture of NaNO2NaNO_2 and dil. HCl on: a. Ethylamine b. Aniline c. Diethylamine. How is nylon 6,6 prepared? What are 'antacids'? Write any 'two' side effects of tranquilizers. OR Explain the mechanism of alkaline hydrolysis of tert-butyl bromide with energy profile diagram. Define carbolic acid. How carbolic acid is prepared from benzene sulphonic acid?

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2017Subjective· 7mImportance★★★★★
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A combined question on nitrous-acid reactions of amines, nylon-6,6 synthesis, and (in the OR branch) the SN1S_N1 mechanism for tert-butyl bromide hydrolysis plus phenol's preparation from benzenesulphonic acid.

a. Action of NaNO2NaNO_2/dil. HCl (generates nitrous acid, HNO2HNO_2, in situ) on:

  • Ethylamine (1° aliphatic amine): forms an unstable aliphatic diazonium salt that decomposes immediately at the reaction temperature, evolving nitrogen gas and giving the alcohol: C2H5NH2+HNO2→C2H5OH+N2↑+H2OC_2H_5NH_2 + HNO_2 \rightarrow C_2H_5OH + N_2\uparrow + H_2O.

  • Aniline (1° aromatic amine): at low temperature (0–5°C), aniline forms a comparatively stable diazonium salt, benzenediazonium chloride: C6H5NH2+NaNO2+2HCl→0−5∘CC6H5N2+Cl−+NaCl+2H2OC_6H_5NH_2 + NaNO_2 + 2HCl \xrightarrow{0-5^\circ C} C_6H_5N_2^+Cl^- + NaCl + 2H_2O (this diazotisation reaction is the entry point to azo-dye and coupling chemistry).

  • Diethylamine (2° amine): secondary amines react with HNO2HNO_2 to give a yellow, oily N-nitroso compound: (C2H5)2NH+HNO2→(C2H5)2N−NO (N-nitrosodiethylamine)+H2O(C_2H_5)_2NH + HNO_2 \rightarrow (C_2H_5)_2N-NO\ (\text{N-nitrosodiethylamine}) + H_2O.

b. Preparation of nylon-6,6: nylon-6,6 is a condensation polymer made by heating hexamethylenediamine (H2N(CH2)6NH2H_2N(CH_2)_6NH_2) with adipic acid (hexanedioic acid, HOOC(CH2)4COOHHOOC(CH_2)_4COOH) under high pressure and temperature; the amine and acid groups condense repeatedly, eliminating water at each step, to form amide (peptide-like) linkages:

nH2N(CH2)6NH2+nHOOC(CH2)4COOH→[−NH(CH2)6NHCO(CH2)4CO−]n+2nH2OnH_2N(CH_2)_6NH_2 + nHOOC(CH_2)_4COOH \rightarrow [-NH(CH_2)_6NHCO(CH_2)_4CO-]_n + 2nH_2O

c. Antacids: substances (e.g. NaHCO3NaHCO_3, Mg(OH)2Mg(OH)_2, Al(OH)3Al(OH)_3) that neutralise excess hydrochloric acid secreted in the stomach, relieving acidity/heartburn.

d. Two side effects of tranquilizers: (i) drowsiness/sedation and impaired alertness or motor coordination,

(ii) risk of dependence/addiction and withdrawal symptoms with prolonged use.


OR — Mechanism of alkaline hydrolysis of tert-butyl bromide (SN1S_N1): tert-butyl bromide, (CH3)3C−Br(CH_3)_3C-Br, is a tertiary halide and reacts with aqueous NaOHNaOH by the SN1S_N1 (substitution nucleophilic unimolecular) pathway:

Step 1 (slow, rate-determining): the C–Br bond ionises heterolytically, forming a planar, resonance/hyperconjugation-stabilised tertiary carbocation and a bromide ion: (CH3)3C−Br→(CH3)3C++Br−(CH_3)_3C-Br \rightarrow (CH_3)_3C^+ + Br^-.

Step 2 (fast): the hydroxide ion (a strong nucleophile) rapidly attacks the planar carbocation from either face, giving the alcohol: (CH3)3C++OH−→(CH3)3C−OH(CH_3)_3C^+ + OH^- \rightarrow (CH_3)_3C-OH.

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