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Answer the following questions · Q3

Q.Draw isomers in each of the following

(a) [Pt(NH3)2ClNO2]
(b) [Ru(NH3)4Cl2]
(c) [Cr(en)2Br2]+
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Step 1. (a) [Pt(NH3)2ClNO2]. Square planar Pt(II) with two identical NH3 (A), one Cl (B) and one NO2 (C) -- an MA2BC-type complex (section 9.7.1). Cis isomer: the two NH3 occupy adjacent corners of the square. Trans isomer: the two NH3 occupy diagonally opposite corners, with Cl and NO2 filling the remaining two adjacent corners. (Since NO2- is also ambidentate, section 9.7.2a, each geometric isomer could further show nitro/nitrito linkage isomerism, though the question's main focus is the cis/trans pair.)

Step 2. (b) [Ru(NH3)4Cl2]. Octahedral, MA4B2-type (4 NH3, 2 Cl). Cis isomer: the two Cl occupy adjacent octahedral positions (90 degrees apart). Trans isomer: the two Cl occupy opposite positions (180 degrees apart), with the four NH3 filling the equatorial plane between them.

Step 3. (c) [Cr(en)2Br2]+. Octahedral, M(AA)2B2-type (2 bidentate en, 2 Br). Cis isomer: the two Br adjacent; this form has no internal mirror plane and is CHIRAL, existing as a further d/l enantiomer pair (exactly as for [PtCl2(en)2]2+, Fig. 9.7.1-f). Trans isomer: the two Br opposite; this form has an internal mirror plane and is achiral.

✓Final answer

(a) cis/trans [Pt(NH3)2ClNO2].

(b) cis/trans [Ru(NH3)4Cl2].

(c) cis/trans [Cr(en)2Br2]+, cis form chiral (d/l pair).

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