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Answer the following in brief · Q5

Q.v. Construct a galvanic cell from the electrodes Co3+∣^{3+}\vertCo and Mn2+∣^{2+}\vertMn. ECo0E^0_{Co} = 1.82 V, EMn0E^0_{Mn} = - 1.18V. Calculate Ecell0E^0_{cell}.

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Step 1. Between Co3+/Co (E0=1.82V) and Mn2+/Mn (E0=-1.18V), Co3+/Co has the higher standard potential, so it is the cathode; Mn2+/Mn is the anode.

Step 2. Cell notation, anode on left and cathode on right: Mn(s)∣Mn2+∣∣Co3+∣Co(s)Mn(s)|Mn^{2+}||Co^{3+}|Co(s). …

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