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Answer in one or two sentences · Q8

Q.viii. Formulate a cell from the following electrode reactions : Au3+(aq)+3e−⟶Au(s)\mathrm{Au^{3+}(aq) + 3e^- \longrightarrow Au(s)} Mg(s)⟶Mg2+(aq)+2e−\mathrm{Mg(s) \longrightarrow Mg^{2+}(aq) + 2e^-}

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Step 1. Au3+(aq)+3e−→Au(s)Au^{3+}(aq)+3e^-\rightarrow Au(s) is a reduction reaction, so this electrode is the cathode.

Step 2. Mg(s)→Mg2+(aq)+2e−Mg(s)\rightarrow Mg^{2+}(aq)+2e^- is an oxidation reaction, so this electrode is the anode. …

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