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Q.Write electrode reactions and overall cell reaction for Daniel cell you learnt in standard XI.

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Step 1. In the Daniel cell, zinc is the anode; it is oxidised: Zn(s)→Zn2+(aq)+2e−Zn(s)\rightarrow Zn^{2+}(aq)+2e^-.

Step 2. Copper is the cathode; Cu2+ ions are reduced there: Cu2+(aq)+2e−→Cu(s)Cu^{2+}(aq)+2e^-\rightarrow Cu(s).

Step 3. Both half reactions already balance at 2 electrons, so adding them directly gives the overall cell reaction: Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s)Zn(s)+Cu^{2+}(aq)\rightarrow Zn^{2+}(aq)+Cu(s). …

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