Q.You have learnt Daniel cell in XI th standard. Write notations for anode and cathode. Write the cell formula.
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🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — Galvanic Cell and Salt Bridge
A galvanic (voltaic) cell is built from two half cells (each a metal strip in a solution of its own ions), joined externally through a wire/voltmeter (carrying electrons) and internally by a salt bridge (carrying ionic current). The salt bridge — a U-tube of saturated KCl or NH4NO3 set in agar gel — completes the circuit, prevents the two solutions mixing, and maintains electrical neutrality in both compartments by letting ions migrate as needed. A cell is written in short notation with the anode (–) at the extreme left and cathode (+) at the extreme right, a single vertical line for a phase boundary and a double vertical line for a salt bridge, e.g. Mg(s)∣Mg2+(1M)∣∣Ag+(1M)∣Ag(s). To derive the cell reaction from this n …
Zn (lower E0) is anode; Cu (higher E0) is cathode. …
Step 1. Zn2+/Zn has E0=-0.76V, the lower of the two, so it is the anode, written as Zn(s)∣Zn2+(1M).
Step 2. Cu2+/Cu has E0=+0.34V, the higher of the two, so it is the cathode, written as Cu2+(1M)∣Cu(s). …
Compare E0 values to assign anode/cathode, then apply the cell-notatio …
- Writing the electrode/solution order within each half cell backwards (should be metal-electrode o …
- CBSE 2021Set OC1 markQ.In the Daniel cell, the following redox reaction occurs: Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s). Write the reduction half-cell reaction.
›Reveal solutionSolution
Reduction is the gain of electrons; in the Daniell cell it is the Cu2+ ion that gains electrons and deposits as copper metal.
Identifying the half-reactions
The overall cell reaction is: Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s).
Splitting it: zinc metal is losing electrons to become Zn2+ (oxidation), while Cu2+ ions are gaining electrons to become copper metal (reduction).
Reduction half-reaction
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- CBSE 2021Set OC1 markQ.In the Daniel cell, the following redox reaction occurs: Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s). Write the oxidation half-cell reaction.
›Reveal solutionSolution
Oxidation is the loss of electrons; in the Daniell cell the zinc electrode loses electrons and dissolves into solution as Zn2+.
Identifying the half-reaction
From the overall reaction Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s), zinc metal is converted to Zn2+ ions, which requires the loss of two electrons per Zn atom — this is oxidation.
Oxidation half-reaction
Zn(s)→Zn2+(aq)+2e−
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- CBSE 2021Set OC1 markQ.In the Daniel cell, the following redox reaction occurs: Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s). Write the half-cell reaction which acts as the anode.
›Reveal solutionSolution
The anode is, by definition, the electrode at which oxidation takes place — in the Daniell cell this is the zinc electrode.
Why zinc is the anode
In any galvanic cell, the anode is defined as the electrode where oxidation occurs. Since zinc metal loses electrons and goes into solution as Zn2+ (as shown by the overall reaction Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s)), the zinc electrode is the site of oxidation.
Half-cell reaction at the anode
Zn(s)→Zn2+(aq)+2e−
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- CBSE 2021Set OC1 markQ.In the Daniel cell, the following redox reaction occurs: Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s). Write the half-cell reaction which acts as the cathode.
›Reveal solutionSolution
The cathode is, by definition, the electrode at which reduction takes place — in the Daniell cell this is the copper electrode.
Why copper is the cathode
In any galvanic cell, the cathode is defined as the electrode where reduction occurs. Since Cu2+ ions gain electrons and are deposited as copper metal (from the overall reaction Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s)), the copper electrode is the site of reduction.
Half-cell reaction at the cathode
Cu2+(aq)+2e−→Cu(s)
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- CBSE 2021Set OC1 markQ.In the Daniel cell, the following redox reaction occurs: Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s). Define galvanic cell.
›Reveal solutionSolution
A galvanic cell is an electrochemical device that generates electricity directly from a spontaneous chemical (redox) reaction by keeping oxidation and reduction physically apart.
Definition
A galvanic cell (also called a voltaic cell) is an electrochemical device in which the chemical energy released by a spontaneous (ΔG<0) redox reaction is converted directly into electrical energy. This is achieved by physically separating the oxidation half-reaction and the reduction half-reaction into two different half-cells (each containing an electrode dipped in an electrolyte), connected externally by a wire (through which electrons — and hence current — flow) and internally by a salt bridge (which completes the circuit and maintains electrical neutrality by allowing ion flow).
Example
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