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Question 98 of 119

Q.Write the electronic configuration of the following elements: a. Sulphur (Z = 16) b. Krypton (Z = 36)

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2017Subjective· 2mImportance★★★★★
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Fill orbitals by the Aufbau order up to the given atomic number for each element.

a. Sulphur, Z = 16: filling orbitals in order of increasing energy (1s<2s<2p<3s<3p1s < 2s < 2p < 3s < 3p) with 16 electrons total:

1s2 2s2 2p6 3s2 3p41s^2\,2s^2\,2p^6\,3s^2\,3p^4 — total electrons =2+2+6+2+4=16= 2+2+6+2+4 = 16. ✓ (Sulphur is in Group 16, Period 3, with 6 valence electrons: 3s23p43s^2 3p^4.)

b. Krypton, Z = 36: continuing the Aufbau order (1s,2s,2p,3s,3p,4s,3d,4p1s,2s,2p,3s,3p,4s,3d,4p) for 36 electrons:

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