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Question 116 of 119

Q.Write anomalous behaviour of oxygen with respect to:

(i) Atomicity
(ii) Oxidation state
(iii) Magnetic property
(iv) Nature of hydrides.
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2025Subjective· 2mImportance★★★★★
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O is diatomic (vs polyatomic S/Se/Te), shows only up to +2 (vs +6), O2_2 is paramagnetic, and H2_2O is a liquid (H-bonded) unlike gaseous H2_2S/H2_2Se/H2_2Te.

  1. Atomicity: oxygen exists as a diatomic molecule, O2O_2, while the heavier group-16 members (S, Se, Te) exist as larger polyatomic molecules, e.g. S8S_8 (puckered ring), owing to oxygen's strong tendency to form pπp\pi–pπp\pi multiple bonds instead of long catenated chains.
  2. Oxidation state: oxygen (being the second most electronegative element) shows a very restricted range of oxidation states, mainly −2-2, with −1-1 in peroxides and rarely +2+2 (with F, as in OF2OF_2); it never shows the higher positive states (+4+4, +6+6) that S, Se, Te readily show (e.g. SF6SF_6), because oxygen lacks accessible d orbitals.
  3. Magnetic property: O2O_2 is paramagnetic due to two unpaired electrons in its antibonding π∗\pi^* molecular orbitals (as explained by MO theory), while the corresponding compounds/allotropes of S, Se, Te are diamagnetic. …

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