Q.ii. Which of the following solution will have pH value equal to 1.0 ?
a. 50 mL of 0.1M HCl + 50mL of 0.1M NaOH
b. 60 mL of 0.1M HCl + 40mL of 0.1M NaOH
c. 20 mL of 0.1M HCl + 80mL of 0.1M NaOH
d. 75 mL of 0.2M HCl + 25mLof 0.2M NaOH
Step 1. Check each option by finding the moles of excess H+ (or OH-) after neutralization, then dividing by the total final volume.
Step 2. (a) 50 mL x 0.1M HCl = 5 mmol H+; 50 mL x 0.1M NaOH = 5 mmol OH-. These exactly cancel -- neutral, pH = 7. Not a match.
Step 3. (b) 60 mL x 0.1M HCl = 6 mmol H+; 40 mL x 0.1M NaOH = 4 mmol OH-. Excess H+ = 2 mmol in 100 mL total, so [H+] = 0.02 M, pH = -log(0.02) = 1.70. Not exactly 1.
Step 4. (c) 20 mL x 0.1M HCl = 2 mmol H+; 80 mL x 0.1M NaOH = 8 mmol OH-. Excess OH- = 6 mmol in 100 mL, so basic, pH well above 7. Not a match.
Step 5. (d) 75 mL x 0.2M HCl = 15 mmol H+; 25 mL x 0.2M NaOH = 5 mmol OH-. Excess H+ = 10 mmol in a total volume of 100 mL, so [H+] = 10/100 = 0.1 M, giving pH = -log10(0.1) = 1 exactly. This matches.
d. 75 mL of 0.2M HCl + 25mL of 0.2M NaOH gives excess [H+] = 0.1 M, so pH = 1.
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