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Problems · Problem 2.12

Q.3.4 g of CaCl₂ is dissolved in 2.5 L of water at 300 K. What is the osmotic pressure of the solution? van't Hoff factor for CaCl₂ is 2.47.

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With M2=111M_2 = 111 g mol⁻¹, π=iW2RTM2V=2.47×3.4×0.08206×300111×2.5=0.745\pi = \dfrac{iW_2RT}{M_2V} = \dfrac{2.47 \times 3.4 \times 0.08206 \times 300}{111 \times 2.5} = 0.745 atm.

Step 1. Molar mass of CaCl₂: M2=40+2×35.5=111M_2 = 40 + 2 \times 35.5 = 111 g mol⁻¹.

Step 2. For an electrolyte (section 2.11.2), π=iMRT=iW2RTM2V\pi = iMRT = \dfrac{iW_2RT}{M_2V}. …

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