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Q.Arrange the following solutions in order of increasing osmotic pressure. Assume complete ionization. a) 0.5m Li₂SO₄ b) 0.5m KCl c) 0.5m Al₂(SO₄)₃ d) 0.1m BaCl₂.

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Step 1. Since osmotic pressure (for complete ionisation) is π=iMRT\pi=iMRT, and R and T are the same for all four solutions here, ranking osmotic pressure is equivalent to ranking i×mi \times m (the effective, ion-corrected molar concentration) for each.

Step 2. (a) 0.5m Li2SO4 dissociates as Li2SO4 -> 2Li+ + SO4(2-), giving n=3 ions per formula unit, so i x m = 3 x 0.5 = 1.5.

Step 3. (b) 0.5m KCl dissociates as KCl -> K+ + Cl-, giving n=2, so i x m = 2 x 0.5 = 1.0.

Step 4. (c) 0.5m Al2(SO4)3 dissociates as Al2(SO4)3 -> 2Al(3+) + 3SO4(2-), giving n=5 ions per formula unit, so i x m = 5 x 0.5 = 2.5.

Step 5. (d) 0.1m BaCl2 dissociates as BaCl2 -> Ba(2+) + 2Cl-, giving n=3, so i x m = 3 x 0.1 = 0.3. …

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