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Exercise 4.2 · Q20

Q.Evaluate: ∫0∞xe−x dx\int_0^\infty x e^{-x}\,dx

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∫xe−x dx=−xe−x+∫e−x dx=−xe−x−e−x=−(x+1)e−x.\int x e^{-x}\,dx=-xe^{-x}+\int e^{-x}\,dx=-xe^{-x}-e^{-x}=-(x+1)e^{-x}.

As x→∞x\to\infty, (x+1)e−x→0(x+1)e^{-x}\to0 (exponential decay beats linear growth); at x=0x=0, −(0+1)e0=−1-(0+1)e^0=-1. …

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