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Exercise 4.2 · Q10

Q.Evaluate: ∫3512x+3−2x−3 dx\int_3^5 \dfrac{1}{\sqrt{2x+3}-\sqrt{2x-3}}\,dx

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Multiply numerator and denominator by 2x+3+2x−3\sqrt{2x+3}+\sqrt{2x-3}: the denominator becomes (2x+3)−(2x−3)=6(2x+3)-(2x-3)=6.

∫352x+3+2x−36 dx=118[(2x+3)3/2+(2x−3)3/2]35.\int_3^5\frac{\sqrt{2x+3}+\sqrt{2x-3}}6\,dx=\frac1{18}\Big[(2x+3)^{3/2}+(2x-3)^{3/2}\Big]_3^5. …

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