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Exercise 4.2 · Q11

Q.Evaluate: ∫01x2−2x2+1 dx\int_0^1 \dfrac{x^2-2}{x^2+1}\,dx

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x2−2x2+1=(x2+1)−3x2+1=1−3x2+1.\frac{x^2-2}{x^2+1}=\frac{(x^2+1)-3}{x^2+1}=1-\frac3{x^2+1}. …

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