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Exercise 4.2 · Q33

Q.Evaluate: ∫0π/2sin⁡2x tan⁡−1(sin⁡x) dx\int_0^{\pi/2} \sin 2x \,\tan^{-1}(\sin x)\,dx

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sin⁡2x=2sin⁡xcos⁡x\sin2x=2\sin x\cos x. Let t=sin⁡x, dt=cos⁡x dxt=\sin x,\ dt=\cos x\,dx; limits x=0→t=0x=0\to t=0, x=π/2→t=1x=\pi/2\to t=1.

∫012ttan⁡−1t dt.\int_0^1 2t\tan^{-1}t\,dt.

IBP: u=tan⁡−1t, dv=2t dt⇒v=t2u=\tan^{-1}t,\ dv=2t\,dt\Rightarrow v=t^2.

=t2tan⁡−1t−∫t21+t2 dt=t2tan⁡−1t−(t−tan⁡−1t).=t^2\tan^{-1}t-\int\frac{t^2}{1+t^2}\,dt=t^2\tan^{-1}t-\big(t-\tan^{-1}t\big). …

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