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Exercise 4.2 · Q24

Q.Evaluate: ∫0π/2cos⁡x sin⁡3x dx\int_0^{\pi/2} \sqrt{\cos x}\,\sin^3 x\,dx

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sin⁡3x=sin⁡x(1−cos⁡2x)\sin^3x=\sin x(1-\cos^2x). Let t=cos⁡x, dt=−sin⁡x dxt=\cos x,\ dt=-\sin x\,dx; limits x=0→t=1x=0\to t=1, x=π/2→t=0x=\pi/2\to t=0. …

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