Skip to content
Exercise 4.2 · Q22

Q.Evaluate: ∫0π/4sec⁡2x3tan⁡2x+4tan⁡x+1 dx\int_0^{\pi/4} \dfrac{\sec^2 x}{3\tan^2x+4\tan x+1}\,dx

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
21% · 22/104 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

t=tan⁡x, dt=sec⁡2x dxt=\tan x,\ dt=\sec^2x\,dx; limits x=0→t=0x=0\to t=0, x=π/4→t=1x=\pi/4\to t=1.

∫01dt3t2+4t+1=∫01dt(3t+1)(t+1)=∫01[3/23t+1−1/2t+1]dt=[12ln⁡3t+1t+1]01.\int_0^1\frac{dt}{3t^2+4t+1}=\int_0^1\frac{dt}{(3t+1)(t+1)}=\int_0^1\Big[\frac{3/2}{3t+1}-\frac{1/2}{t+1}\Big]dt=\Big[\frac12\ln\frac{3t+1}{t+1}\Big]_0^1. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.