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Question 149 of 177

Q.Form the differential equation by eliminating arbitrary constants from the relation y=Ae5x+Be−5xy = Ae^{5x} + Be^{-5x}

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2017Subjective· 2mImportance★★★★★
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Differentiate twice and eliminate the arbitrary constants A,BA,B.

y=Ae5x+Be−5xy = Ae^{5x}+Be^{-5x}

dydx=5Ae5x−5Be−5x\dfrac{dy}{dx} = 5Ae^{5x}-5Be^{-5x}

d2ydx2=25Ae5x+25Be−5x=25(Ae5x+Be−5x)=25y\dfrac{d^2y}{dx^2} = 25Ae^{5x}+25Be^{-5x} = 25\big(Ae^{5x}+Be^{-5x}\big) = 25y

So the required differential equation (with A,BA,B eliminated) is: …

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