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Q.Write the order of the differential equation 1+(dydx)2=(d2ydx2)3/2\sqrt{1+\left(\dfrac{dy}{dx}\right)^2}=\left(\dfrac{d^2y}{dx^2}\right)^{3/2}

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2025Subjective· 1mImportance★★★★★
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The order of a differential equation is the order of the highest derivative appearing in it.

The given differential equation is

1+(dydx)2=(d2ydx2)3/2\sqrt{1+\left(\frac{dy}{dx}\right)^2}=\left(\frac{d^2y}{dx^2}\right)^{3/2}

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