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Miscellaneous Exercise 4 (Solve) · Q107

Q.Show that the combined equation of a pair of lines through the origin and each making an angle of α\alpha with the line x+y=0x + y = 0 is x2+2(sec⁡2α)xy+y2=0x^2 + 2(\sec2\alpha)xy + y^2 = 0.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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Slope of x+y=0x+y=0 is −1-1. For a required slope mm: tan⁡α=∣m+11−m∣\tan\alpha=\left|\dfrac{m+1}{1-m}\right|. Squaring and clearing: tan⁡2α(1−m)2=(m+1)2⇒m2(tan⁡2α−1)−2m(tan⁡2α+1)+(tan⁡2α−1)=0\tan^2\alpha(1-m)^2=(m+1)^2 \Rightarrow m^2(\tan^2\alpha-1)-2m(\tan^2\alpha+1)+(\tan^2\alpha-1)=0. Dividing by sec⁡2α=tan⁡2α+1\sec^2\alpha=\tan^2\alpha+1 and using tan⁡2α−1sec⁡2α=sin⁡2α−cos⁡2α=−cos⁡2α\dfrac{\tan^2\alpha-1}{\sec^2\alpha}=\sin^2\alpha-\cos^2\alpha=-\cos2\alpha: −cos⁡2α m2−2m−cos⁡2α=0-\cos2\alpha\,m^2-2m-\cos2\alpha=0; dividing by −cos⁡2α-\cos2\alpha: $m^2+2\ …

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