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Miscellaneous Exercise 4 (Solve) · Q102

Q.Show that the following equations represent a pair of lines, find the acute angle between them: 9x2−6xy+y2+18x−6y+8=09x^2 - 6xy + y^2 + 18x - 6y + 8 = 0.

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9x2−6xy+y2=(3x−y)29x^2-6xy+y^2=(3x-y)^2, so try (3x−y+p)(3x−y+q)=9x2−6xy+y2+3(p+q)x−(p+q)y+pq(3x-y+p)(3x-y+q)=9x^2-6xy+y^2+3(p+q)x-(p+q)y+pq. Matching: 3(p+q)=18⇒p+q=63(p+q)=18 \Rightarrow p+q=6; −(p+q)=−6-(p+q)=-6 ✓; pq=8pq=8. Solving, p=2,q=4p=2,q=4. So the equation factors as (3x−y+2)(3x−y+4)=0(3x-y+2)(3x-y+4)=0: two parallel lines. Since h2−ab=9−9=0h^2-ab=9-9=0, the an …

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