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Miscellaneous Exercise 4 (Solve) · Q66

Q.Find the joint equation of lines: x+y−3=0x + y - 3 = 0 and 2x+y−1=02x + y - 1 = 0.

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✓ Free question

(x+y−3)(2x+y−1)=0(x+y-3)(2x+y-1)=0. Expand: 2x2+xy−x+2xy+y2−y−6x−3y+32x^2+xy-x+2xy+y^2-y-6x-3y+3. Collect: 2x2+3xy+y2−7x−4y+32x^2+3xy+y^2-7x-4y+3.

✓Final answer

2x2+3xy+y2−7x−4y+3=02x^2 + 3xy + y^2 - 7x - 4y + 3 = 0

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