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Exercise 3.3 · Q63

Q.Prove the following: 2tan⁡−113=tan⁡−1342\tan^{-1}\dfrac{1}{3} = \tan^{-1}\dfrac{3}{4}

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With x=y=13x=y=\dfrac13, xy=19<1xy=\dfrac19<1, so property (xiii) applies: $2\tan^{-1}\dfrac13=\tan^{-1}\left(\dfrac{\frac13+\frac13}{1-\frac19}\right)=\tan^{-1}\left(\dfrac{2/3}{8/9}\right)=\tan^{-1}\left(\dfrac23\cdot\d …

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