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Long Answer Questions · Q23

Q.Describe Kelvin's method to determine the resistance of a galvanometer by using a meter bridge.

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Kelvin's method (Section 9.3.1) finds a galvanometer's own resistance G using the ordinary metre-bridge circuit, with the galvanometer itself connected in one gap and a known resistance box R in the other. Procedure: a suitable value is set on the resistance box, the key is closed, and the galvanometer's steady deflection is noted WITHOUT touching the jockey to the wire at all; the rheostat is then adjusted to give a convenient deflection, around two-thirds of full scale. The jockey is next tapped at different points along the wire until a point D is found where the deflection shows NO CHANGE whether the jockey touches the wire there or not -- an unchanging deflection means no current flows between the central strip and D through the jockey, so B (the central strip's node) and D must be at the same potential, exactly the balance condition of an ordinary metre-bridge measurement. The length lgl_g of wire between A and D (opposite the galvanometer arm) and the remaining length lr=100−lgl_r=100-l_g (opposite the resistance-box arm) are then measured. Since the bridge is balanced, G/R=RAD/RDC=lg/lrG/R = R_{AD}/R_{DC} = l_g/l_r, giving

G=R(lg100−lg)G = R\left(\frac{l_g}{100-l_g}\right)

This method's real advantage is that it never needs to pass a potentially damaging, large measuring current directly through the sensitive galvanometer coil to find its resistance. [!ANSWER] G=R lg/(100−lg)G = R\,l_g/(100-l_g).

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