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Question 48 of 57

Q.Disintegration rate of a radio-active sample is 101010^{10} per hour at 20 hours from the start. It reduces to 5×1095 \times 10^{9} per hour after 30 hours. Calculate the decay constant.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2023Subjective· 2mImportance★★★★★
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Radioactive decay law R=R0e−λtR=R_0e^{-\lambda t} applied between two known activities.

The disintegration rate follows R=R0e−λtR = R_0 e^{-\lambda t}, so the ratio of activities at two times separated by Δt=30−20=10\Delta t = 30-20=10 h is

R(30)R(20)=e−λΔt\frac{R(30)}{R(20)} = e^{-\lambda\Delta t}

5×1091010=0.5=e−10λ\frac{5\times10^9}{10^{10}} = 0.5 = e^{-10\lambda}

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