Skip to content
Questions 3-25 · Q7

Q.Describe Young's double slit interference experiment and derive conditions for occurrence of dark and bright fringes on the screen. Define fringe width and derive a formula for it.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
37% · 31/83 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

In Young's double slit experiment, a plane wavefront is made to fall on an opaque screen AB pierced by two narrow, identical, closely-spaced (a few mm apart) parallel slits S1S_1 and S2S_2, with their lengths perpendicular to the plane of the diagram; a linear source S (or a source at the focus of a converging lens) supplies the plane wavefront, and S1,S2S_1,S_2 are taken equidistant from S so both receive the light in phase. An observing screen PQ is placed behind AB, at distance D. Reaching S1S_1 and S2S_2 in phase, both slits act as coherent secondary sources emitting cylindrical wavelets that overlap and interfere in the region beyond AB, producing alternating bright and dark FRINGES on PQ.

To locate the fringes: set x along the original propagation direction, with the screen along the y-z plane; O is the midpoint of S1S2S_1S_2 (separation d) and O' the point on the screen directly opposite O, at distance D (with D≫dD\gg d). For a general screen point P at height y above O', (S2P)2−(S1P)2=[D2+(y+d/2)2]−[D2+(y−d/2)2]=2yd(S_2P)^2-(S_1P)^2=\left[D^2+(y+d/2)^2\right]-\left[D^2+(y-d/2)^2\right]=2yd. Factoring the left side as (S2P−S1P)(S2P+S1P)(S_2P-S_1P)(S_2P+S_1P), and using S2P+S1P≈2DS_2P+S_1P\approx2D (valid since d≪Dd\ll D), gives the path difference Δl=S2P−S1P≈ydD\Delta l=S_2P-S_1P\approx\dfrac{yd}{D}. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.