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Choose the Best Answer · Q8

Q.IUPAC name of CH3-CH(C2H5)-C(C4H9)(CH3)-CH3, i.e. CH3-C(H)(C2H5)-C(C4H9)(CH3)-CH3 drawn as a 4-carbon backbone CH3-C-C-CH3 in which the second carbon carries H (implicit) and an ethyl (C2H5) substituent, and the third carbon carries a butyl (C4H9) substituent and a methyl (CH3) substituent, is

a) 3,4,4-Trimethylheptane
b) 2-Ethyl-3,3-dimethylheptane
c) 3,4,4-Trimethyloctane
d) 2-Butyl-2-methyl-3-ethyl-butane
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Step 1. As drawn, the visible 4-carbon backbone is CH3-CH(C2H5)-C(C4H9)(CH3)-CH3, where the second carbon carries an ethyl branch and the third carries both a butyl and a methyl branch.

Step 2. Since the ethyl branch (2 carbons) is LONGER than the terminal methyl it's attached alongside, and the butyl branch (4 carbons) is longer than the chain's other terminal methyl, the TRUE longest chain routes through both: [2 ethyl carbons]-C(bearing 1 methyl)-C(bearing 2 methyls)-[4 butyl carbons] = 8 carbons total (octane). …

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