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Choose the Best Answer · Q10

Q.C(diamond) →\rightarrow C(graphite), ΔH\Delta H = –ve, this indicates that

(a) graphite is more stable than diamond
(b) graphite has more energy than diamond
(c) both are equally stable
(d) stability cannot be predicted
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Step 1. ΔH=Hgraphite−Hdiamond\Delta H=H_{graphite}-H_{diamond} is negative, meaning Hgraphite<HdiamondH_{graphite}<H_{diamond} -- graphite sits at LOWER internal/enthalpy content.

Step 2. Lower energy content corresponds to greater thermodynamic stability (Section ~7.2.5's discussion of graphite vs diamond as different-energy forms of carbon), so graphite is the more stable allotrope -- consistent with the fact that diamond, though …

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