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Write Brief Answer · Q30

Q.Calculate the entropy change in the system, and surroundings, and the total entropy change in the universe during a process in which 245 J of heat flow out of the system at 77∘77^\circC to the surrounding at 33∘33^\circC.

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Step 1. Tsystem=77+273=350T_{system}=77+273=350 K, Tsurroundings=33+273=306T_{surroundings}=33+273=306 K; 245 J of heat flows OUT of the system (into the surroundings).

Step 2. Entropy change of the system (losing heat, so qq is negative for the system): ΔSsys=qsys/Tsys=−245/350=−0.70\Delta S_{sys}=q_{sys}/T_{sys}=-245/350=-0.70 J K−1^{-1}.

Step 3. Entropy change of the surroundings (gaining the same 245 J, at its own temperature): ΔSsurr=+245/306=+0.80\Delta S_{surr}=+245/306=+0.80 J K−1^{-1}. …

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