Skip to content
Choose the Best Answer · Q15

Q.The work done by the liberated gas when 55.85 g of iron (molar mass 55.85 g mol−1^{-1}) reacts with hydrochloric acid in an open beaker at 25∘25^\circC is

(a) – 2.48 kJ
(b) – 2.22 kJ
(c) + 2.22 kJ
(d) + 2.48 kJ
Puducherry TnboardTextbookSubjectiveImportance★★★★★
32% · 29/92 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1. Fe(s)+2HCl(aq)→FeCl2(aq)+H2(g)Fe(s)+2HCl(aq)\rightarrow FeCl_2(aq)+H_2(g); moles Fe =55.85/55.85=1=55.85/55.85=1 mol, so exactly 1 mole of H2(g)_2(g) is liberated, giving Δn(g)=+1\Delta n_{(g)}=+1. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.