Concept understanding — Conservation of Angular Momentum
Conservation of Angular Momentum
The Intuition First
Imagine you're sitting on a spinning office chair with your arms stretched out. Someone gives you a gentle push, and you start rotating slowly. Now pull your arms in tight against your chest. What happens? You spin faster. Push your arms back out — you slow down again.
Nothing external pushed you to go faster or slower. The change came from inside — from how you arranged your mass relative to the axis of rotation.
That's the core idea: Angular momentum is a quantity that stays constant for a rotating system unless an external torque acts on it. When you pulled your arms in, you didn't change your angular momentum — you changed your distribution of mass, and your rotation speed had to adjust to keep the total constant.
The Precise Statement
L=constantifτext=0
Where:
L is the angular momentum of the system
τext is the net external torque acting on the system
In words: The total angular momentum of an isolated system (no external torque) remains constant in both magnitude and direction.
What Is Angular Momentum?
For a point mass m moving with velocity v at position r from a reference point:
L=r×mv
For a rigid body rotating about a fixed axis:
L=Iω
Where:
I = moment of inertia (how mass is distributed relative to the axis)
ω = angular velocity (how fast it spins)
Note
Moment of inertia I depends on where the mass is, not just how much. Mass far from the axis gives larger I; mass close to the axis gives smaller I.
Why It Works: The Physics
Newton's second law for rotation says:
τext=dtdL
If τext=0, then dtdL=0, so L is constant.
Since L=Iω, if I changes (you pull arms in), ω must change in the opposite way to keep L the same:
I1ω1=I2ω2
Smaller I → larger ω (spin faster). Larger I → smaller ω (spin slower).
Real-World Examples
Situation
What happens
Why
Ice skater pulling arms in
Spins faster
I decreases, ω increases to keep L constant
Diver tucking into a ball
Rotates faster in midair
Same principle — no external torque during flight
Cat falling upside-down
Twists body to land on feet
Changes I of different body parts to rotate without external torque
Planet orbiting the Sun
Speeds up when closer, slows down when farther
Gravitational force is central (torque = 0), so L is constant
Watch out
Angular momentum is a vector. Its direction matters too. If no external torque acts, the axis of rotation stays fixed in space. This is why a spinning gyroscope or a bicycle wheel resists being tilted.
Common Mistake to Avoid
Students often think "angular momentum is conserved" means "angular velocity is constant." That's false. Angular velocity can change if the moment of inertia changes. What stays constant is the productIω.
Also: conservation applies only when net external torque is zero. If you apply a brake to a spinning wheel, torque is present — angular momentum is not conserved for the wheel alone (though it is conserved for wheel + brake + Earth as a system).
The Big Picture
Conservation of angular momentum is one of the three great conservation laws in physics (along with energy and linear momentum). It's a direct consequence of the rotational symmetry of space — the laws of physics don't care which direction you're facing. That deep symmetry gives us this powerful tool for solving problems, from planetary orbits to quantum spins.
When you next see an ice skater spin faster by pulling arms in, you're watching one of the most elegant principles of physics in action: nature conserves rotation.
This topic frequently turns up in searches like "Conservation of Angular Momentum: definition, formula and real-world examples" — Conservation of Angular Momentum sits squarely within the System of Particles and Rotational Motion coverage of NCERT Class 11 Physics, so it is fair game for both CBSE board questions and competitive-exam numericals. Cross-checking this explanation against the relevant NCERT Physics chapter and solving a few past-year questions will round out your preparation.
Momentum p=mv is perpendicular to the position vector r only where the planet's velocity is purely tangential -- and that happens exactly at perihelion and aphelion.
✓Final answer
(a) perihelion and aphelion
Step 1. In general, a planet's velocity has both a radial component (changing its distance from the Sun) and a tangential component (changing its angular position). p⊥r only when the radial component of velocity is zero, i.e. the distance from the Sun is momentarily not changing.
Step 2. The distance r(t) stops changing (its derivative is zero) exactly at the two turning points of the orbit: the closest point (perihelion) and the farthest point (aphelion) -- everywhere else along the ellipse, the planet is either approaching or receding from the Sun, so it has a nonzero radial velocity component.
Step 3. At every other point on the orbit, therefore, v (and hence p) has some radial component, so p is not exactly perpendicular to r.
Step 4. Eliminating the others: (b) is wrong since p⊥r fails everywhere except the two turning points; (c) is wrong because aphelion satisfies the same perpendicularity condition as perihelion; (d) is wrong since it does happen, just only at those two points.
✓Final answer
(a) perihelion and aphelion.
Identify where the radial velocity component vanishes along an elliptical orbit.
Assuming momentum is perpendicular to position everywhere on an orbit, not just at the two apsides.
Forgetting that aphelion satisfies the same condition as perihelion.