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I. Multiple Choice Questions · Q1

Q.The linear momentum and position vector of the planet is perpendicular to each other at

(a) perihelion and aphelion
(b) at all points
(c) only at perihelion
(d) no point
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✓ Free question

Step 1. In general, a planet's velocity has both a radial component (changing its distance from the Sun) and a tangential component (changing its angular position). p⃗⊥r⃗\vec p \perp \vec r only when the radial component of velocity is zero, i.e. the distance from the Sun is momentarily not changing.

Step 2. The distance r(t)r(t) stops changing (its derivative is zero) exactly at the two turning points of the orbit: the closest point (perihelion) and the farthest point (aphelion) -- everywhere else along the ellipse, the planet is either approaching or receding from the Sun, so it has a nonzero radial velocity component.

Step 3. At every other point on the orbit, therefore, v⃗\vec v (and hence p⃗\vec p) has some radial component, so p⃗\vec p is not exactly perpendicular to r⃗\vec r.

Step 4. Eliminating the others: (b) is wrong since p⃗⊥r⃗\vec p \perp \vec r fails everywhere except the two turning points; (c) is wrong because aphelion satisfies the same perpendicularity condition as perihelion; (d) is wrong since it does happen, just only at those two points.

✓Final answer

(a) perihelion and aphelion.

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