Assume that you are in another solar system and are provided with the set of data given below, consisting of the planets' semi-major axes and time periods. Can you infer the relation connecting semi-major axis and time period? | Planet (imaginary) | Time period T (in years) | Semi-major axis a (in AU) |\n|---|---|---|\n| Kurinji | 2 | 8 |\n| Mullai | 3 | 18 |\n| Marutham | 4 | 32 |\n| Neithal | 5 | 50 |\n| Paalai | 6 | 72 |
Imagine you're watching two planets orbiting the Sun. One is close in — Mercury, zipping around in just 88 days. Another is far out — Saturn, taking nearly 30 years to complete one lap. You'd expect the farther planet to take longer, but here's the surprising part: the relationship isn't just "farther = slower." It's much more precise, and it reveals a deep truth about gravity itself.
The Intuition
Think of a planet as a runner on a circular track. The farther out the track, the longer the lap — that's obvious. But Kepler noticed something subtler: if you double the distance from the Sun, the orbital period doesn't just double. It increases by a factor of about 2.8 (which is 8). Triple the distance, and the period grows by about 5.2 (which is 27).
There's a pattern here. The period seems to grow as the 3/2 power of the distance. Why? Because gravity weakens with distance, so a farther planet feels a weaker pull and moves more slowly — not just because the track is longer, but because it's moving slower along that track.
The Precise Statement
T2∝a3
The square of the orbital period T is proportional to the cube of the semi-major axis a of the orbit.
For planets orbiting the Sun, if you measure T in Earth years and a in astronomical units (AU, where 1 AU = Earth's average distance from the Sun), the constant of proportionality is exactly 1:
T2=a3
So for Earth: T=1 year, a=1 AU, and 12=13 — it checks out.
For Mars: a≈1.52 AU, so T2=(1.52)3≈3.51, giving T≈1.87 years. That's about 687 days — exactly right.
Note
This law applies to any body orbiting a much more massive central body: moons around planets, satellites around Earth, binary stars around each other. The constant of proportionality changes depending on the mass of the central body.
Why It Works (The Physics)
Newton later showed that Kepler's Third Law is a direct consequence of his law of gravitation. For a circular orbit (a good approximation for most planets), the centripetal force needed to keep the planet in orbit is provided by gravity:
r2GMm=rmv2
Here M is the Sun's mass, m the planet's mass, r the orbital radius, and v the orbital speed. The speed is related to the period by v=2πr/T. Substituting and simplifying:
r2GM=T24π2r
Rearranging:
T2=GM4π2r3
The quantity 4π2/(GM) is a constant for all planets orbiting the Sun. So T2∝r3 — exactly Kepler's law.
Important
The constant 4π2/(GM) depends only on the mass of the central body. This means: if you know the period and distance of any moon or planet, you can calculate the mass of the body it orbits. This is how astronomers "weigh" stars, black holes, and galaxies.
A Common Mistake
Watch out
Many students think the law says T∝a3/2 — which is true — but then assume that doubling the distance doubles the period. It doesn't. Doubling a multiplies T by 23/2≈2.83. The period grows faster than the distance.
The Big Picture
Kepler's Third Law is the key that unlocks the solar system's scale. Before Kepler, astronomers knew the relative distances of planets (e.g., Mars is about 1.5 times farther than Earth), but not the absolute distances. Once you measure one planet's period and distance in real units (say, Earth's 1 year and 1 AU), the law gives you every other planet's distance in kilometers — just by timing their orbits.
It also works in reverse: observe a star's wobble caused by an orbiting planet, measure the planet's period, and you can calculate how far the planet is from the star. This is how most exoplanets are discovered.
Final takeaway: Kepler's Third Law is a simple, beautiful relationship — T2∝a3 — that connects how long an orbit takes to how far out it is. It works because gravity follows an inverse-square law, and it lets us measure the masses of astronomical objects.
Looking up "Kepler's Third Law: definition, formula & real-world examples" is a good habit before an exam, and it is worth knowing that Kepler's Third Law is drawn directly from the Gravitation coverage of the NCERT/CBSE Class 11 Physics syllabus and recurs often in JEE Main and NEET papers. Cross-checking this explanation against the relevant NCERT Physics chapter and solving a few past-year questions will round out your preparation.
Checking T2/a for every row gives the same constant (0.5), so T2∝a -- not the usual a3∝T2 of our own solar system.
✓Final answer
a∝T2 (equivalently T2/a=0.5 for every planet in this imaginary system) -- a different relation from Kepler's third law in our own solar system.
Step 1. Tabulate T2 and a for each imaginary planet: Kurinji (T=2,a=8): T2=4; Mullai (T=3,a=18): T2=9; Marutham (T=4,a=32): T2=16; Neithal (T=5,a=50): T2=25; Paalai (T=6,a=72): T2=36.
Step 2. Compute the ratio T2/a for each: 4/8=0.5, 9/18=0.5, 16/32=0.5, 25/50=0.5, 36/72=0.5 -- every single row gives exactly the same constant, 0.5.
Step 3. Since T2/a is constant (not T2/a3), the relation connecting the two quantities in this data set is T2∝a, i.e. a∝T2.
Step 4. This is a genuinely different relation from our own solar system's Kepler's third law (T2∝a3) -- it shows that the exponent in such a power-law relation must always be checked directly against the data, not assumed by analogy with a different system.
✓Final answer
a∝T2 (equivalently T2/a=0.5, a constant) -- not a3∝T2 as in Kepler's third law for our own solar system.
Compute T^2/a (and, for comparison, a^3/T^2) for each row and see which ratio is genuinely constant.
Assuming the relation must be Kepler's third law (a^3 proportional to T^2) by analogy, without actually checking the numbers.
Mixing up which ratio (T^2/a vs T^2/a^3) is the one that comes out constant for this particular data set.