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IV. Exercises · Q15

Q.Calculate the change in gg value in your district of Tamil Nadu. (Hint: Get the latitude of your district of Tamil Nadu from Google.) What is the difference in gg values at Chennai and Kanyakumari?

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Step 1. Use g′=g−ω2Rcos⁡2λg'=g-\omega^2R\cos^2\lambda, where ω2R≈3.4×10−2 m s−2\omega^2R\approx3.4\times10^{-2}\ \text{m s}^{-2} (computed from Earth's rotation rate and radius, as in the chapter's worked latitude example).

Step 2. Chennai's latitude is about 13∘13^\circ. Converting to radians and computing: cos⁡13∘≈0.974\cos13^\circ\approx0.974, cos⁡213∘≈0.949\cos^213^\circ\approx0.949. So gChennai≈9.8−(3.4×10−2)(0.949)≈9.8−0.0323≈9.7677 m s−2g_{Chennai}\approx9.8-(3.4\times10^{-2})(0.949)\approx9.8-0.0323\approx9.7677\ \text{m s}^{-2}.

Step 3. Kanyakumari, at the southern tip of Tamil Nadu, has a lower latitude, about 8.1∘8.1^\circ (closer to the equator). cos⁡8.1∘≈0.990\cos8.1^\circ\approx0.990, cos⁡28.1∘≈0.980\cos^28.1^\circ\approx0.980. So gKanyakumari≈9.8−(3.4×10−2)(0.980)≈9.8−0.0333≈9.7667 m s−2g_{Kanyakumari}\approx9.8-(3.4\times10^{-2})(0.980)\approx9.8-0.0333\approx9.7667\ \text{m s}^{-2}.

Step 4. Difference: Δg=gChennai−gKanyakumari≈9.7677−9.7667=0.0010 m s−2\Delta g=g_{Chennai}-g_{Kanyakumari}\approx9.7677-9.7667=0.0010\ \text{m s}^{-2}. …

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