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IV. Exercises · Q3

Q.If the masses and mutual distance between two objects are doubled, what is the change in the gravitational force between them?

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✓ Free question

Step 1. Original force: F=Gm1m2r2F=\dfrac{Gm_1m_2}{r^2}.

Step 2. With m1→2m1m_1\to2m_1, m2→2m2m_2\to2m_2 and r→2rr\to2r: F′=G(2m1)(2m2)(2r)2=4Gm1m24r2=Gm1m2r2=FF'=\dfrac{G(2m_1)(2m_2)}{(2r)^2}=\dfrac{4Gm_1m_2}{4r^2}=\dfrac{Gm_1m_2}{r^2}=F.

Step 3. The factor of 4 gained from doubling both masses exactly cancels the factor of 4 lost from doubling the (squared) distance.

✓Final answer

F′=FF'=F -- there is no change in the gravitational force.

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