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IV. Exercises · Q7

Q.If the angular momentum of a planet is given by L⃗(t)=−5t2 i^−6t j^+3k^\vec{L}(t) = -5t^2\,\hat{i} - 6t\,\hat{j} + 3\hat{k}, what is the torque experienced by the planet? Will the torque be in the same direction as that of the angular momentum?

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Step 1. Torque is the time rate of change of angular momentum: τ⃗=dL⃗dt\vec\tau=\dfrac{d\vec L}{dt}.

Step 2. Differentiating L⃗(t)=−5t2i^−6tj^+3k^\vec L(t)=-5t^2\hat i-6t\hat j+3\hat k term by term: ddt(−5t2)=−10t\dfrac{d}{dt}(-5t^2)=-10t, ddt(−6t)=−6\dfrac{d}{dt}(-6t)=-6, and the constant term 3k^3\hat k differentiates to zero.

Step 3. So τ⃗=−10t i^−6 j^\vec\tau=-10t\,\hat i-6\,\hat j -- a vector with only i^\hat i and j^\hat j components, and no k^\hat k component at all, and with a time-varying i^\hat i part. …

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