Skip to content
II. Short Answer Questions · Q32

Q.Give an expression for work done in an isothermal process.

Puducherry TnboardTextbookSubjectiveImportance★★★★★est
68% · 86/126 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1. For an isothermal process, work done is W=∫ViVfP dVW=\int_{V_i}^{V_f}P\,dV; using the ideal gas law P=μRT/VP=\mu RT/V (with TT constant) inside the integral gives W=μRT∫ViVfdVVW=\mu RT\int_{V_i}^{V_f}\dfrac{dV}{V}.

Step 2. Since TT is constant, μRT\mu RT can be taken outside the integral, and ∫ViVfdVV=ln⁡(VfVi)\int_{V_i}^{V_f}\dfrac{dV}{V}=\ln\left(\dfrac{V_f}{V_i}\right). …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.