Q.0.5 mole of an ideal gas at 300 K, expands isothermally from an initial volume of 2 L to a final volume of 6 L. Calculate :

An isothermal process is one in which the temperature of a thermodynamic system stays constant while its pressure and volume are free to change. Since $PV=\mu RT$ and $T$ is fixed, the equation of state becomes $PV = \text{constant}$, so if the gas moves from $(P_1,V_1)$ to $(P_2,V_2)$, then $P_1V_1=P_2V_2$; on a P-V diagram this traces a hyperbola called an isotherm, with a curve closer to the origin corresponding to a lower temperature. Since $U$ for an ideal gas depends only on $T$, and $T$ is constant, $\Delta U = 0$ throughout an isothermal process, so the first law reduces to $Q=W$: all the heat supplied is used entirely to do external work (isothermal expansion, $Q,W>0$), or all the work done on the gas during compression flows straight out as heat ($Q,W<0$). The wor …