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Question 64 of 68

Q.A gas of 0.5 mole at 300 K expands isothermally from an initial volume of 2.0 litre to a final volume of 6.0 litre. What is the work done by gas?

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2025Subjective· 2mImportance★★★★★
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The work done in an isothermal expansion of an ideal gas is nRTln⁡(V2/V1)nRT\ln(V_2/V_1).

For an isothermal process on nn moles of an ideal gas at temperature TT, the work done by the gas expanding from V1V_1 to V2V_2 is

W=nRTln⁡(V2V1)W = nRT\ln\left(\dfrac{V_2}{V_1}\right)

Given n=0.5 moln = 0.5\text{ mol}, T=300 KT = 300\text{ K}, R=8.31 J mol−1K−1R = 8.31\text{ J mol}^{-1}\text{K}^{-1}, V1=2.0 LV_1 = 2.0\text{ L}, V2=6.0 LV_2 = 6.0\text{ L}:

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