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I. Multiple Choice Questions · Q12

Q.If sPs_P and sVs_V denote the specific heats of nitrogen gas per unit mass at constant pressure and constant volume respectively, then (JEE 2007)

(a) sP−sV=28Rs_P - s_V = 28R
(b) sP−sV=R/28s_P - s_V = R/28
(c) sP−sV=R/14s_P - s_V = R/14
(d) sP−sV=Rs_P - s_V = R
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Step 1. Meyer's relation gives the MOLAR specific heats: CP−CV=RC_P-C_V=R (per mole of gas).

Step 2. Specific heat PER UNIT MASS, ss, is the molar specific heat divided by the molar mass: s=C/Ms=C/M.

Step 3. Nitrogen gas is diatomic, N2N_2, with molar mass M=28 g mol−1M=28\ \text{g mol}^{-1}. Dividing Meyer's relation through by MM: sP−sV=CP−CVM=R28s_P-s_V=\dfrac{C_P-C_V}{M}=\dfrac{R}{28}. …

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