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IV. Numerical Problems · Q7

Q.Calculate the mean free path of air molecules at STP. The diameter of N2N_2 and O2O_2 is about 3×10−103\times10^{-10} m

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Step 1. STP: T=273T=273 K, P=1.013×105P=1.013\times10^5 Pa, k=1.38×10−23 J K−1k=1.38\times10^{-23}\ \text{J K}^{-1}, d=3×10−10d=3\times10^{-10} m.

Step 2. Number density: n=PkT=1.013×1051.38×10−23×273≈2.69×1025 m−3n=\dfrac{P}{kT}=\dfrac{1.013\times10^5}{1.38\times10^{-23}\times273}\approx2.69\times10^{25}\ \text{m}^{-3}.

Step 3. πd2=π×(3×10−10)2=π×9×10−20≈2.827×10−19 m2\pi d^2=\pi\times(3\times10^{-10})^2=\pi\times9\times10^{-20}\approx2.827\times10^{-19}\ \text{m}^2. …

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