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I. Multiple Choice Questions · Q9

Q.If the temperature and pressure of a gas is doubled the mean free path of the gas molecules

(a) remains same
(b) doubled
(c) tripled
(d) quadrapoled
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Step 1. From Section ~9.5.1, the mean free path is λ=kT2 πd2P\lambda=\dfrac{kT}{\sqrt2\,\pi d^2P}, directly proportional to TT and inversely proportional to PP.

Step 2. If both T→2TT\to2T and P→2PP\to2P, the new mean free path is λ′=k(2T)2 πd2(2P)=22⋅kT2 πd2P=λ\lambda'=\dfrac{k(2T)}{\sqrt2\,\pi d^2(2P)}=\dfrac{2}{2}\cdot\dfrac{kT}{\sqrt2\,\pi d^2P}=\lambda.

Step 3. The factor of 2 in the numerator (from doubled T) exactly cancels the factor of 2 in the denominator (from doubled P), so λ\lambda is completely unchanged. …

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