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III. Long Answer Questions · Q7

Q.Derive the expression for mean free path of the gas.

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Step 1. Consider molecules of diameter dd, with nn molecules per unit volume. Assume, for the counting argument, that only one molecule (average speed vv) moves while the rest are momentarily at rest.

Step 2. In time tt, the moving molecule sweeps out a path of length vtvt, colliding with any stationary molecule whose centre lies within an imaginary cylinder of length vtvt and cross-section πd2\pi d^2 around its path.

Step 3. The number of collisions in time tt equals the number of molecules inside that cylinder's volume: πd2vt×n\pi d^2vt\times n.

Step 4. Mean free path (first approximation) =distance travellednumber of collisions=vtπd2vtn=1πd2n=\dfrac{\text{distance travelled}}{\text{number of collisions}}=\dfrac{vt}{\pi d^2vtn}=\dfrac{1}{\pi d^2n}. …

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